Magical Mathematics[Interesting Approach]> ALgebra...
1 Answers
Last Activity: 14 Years ago
Dear aritra,
If 1st digit is odd 50% of no.s can be there in last two places.
if it is odd rest 50% can be there.
till 1 to 8 in first place sum of last two=4*((101*100)/2)=4*5050=20200
if 9 rests at 1st place sum=5050/2=2525
so total=20200+2525=22725
but we have to add hundred's place. so sum of hundred's place is 50*(100+200+300+400+500+600+700+800+900)…
so sum=225000+22725=247725
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 1 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
